【探讨】你真的了解 RTOS 的多线程吗？欢迎各位大佬来分析~

发布于 2019-12-09 17:47:19 浏览：2202 订阅该版

* 本帖最后由 aozima 于 2019-12-10 11:51 编辑 *

**在 RT-Thread msh(优先级20) 运行 demo1 demo2  demo3 3条分别打印什么，为什么这样打印（先别运行哦，直接分析看你了解透彻没）？**:lol:lol 
**先仅仅作者能看回帖，2天后揭晓大家的分析~**

```#include <rtthread.h>

static void thread1_entry(void *parameter)
{
    rt_thread_mdelay(100);
    while (1)
    {
        rt_kprintf("1");
    }
}

static void thread2_entry(void *parameter)
{
    rt_thread_mdelay(500);
    while (1)
    {
        rt_kprintf("2");
    }
}

static void sample1_demo(void)
{
    rt_thread_t tid1 = rt_thread_create("task1", thread1_entry, RT_NULL, 512, 25, 5);
    if (tid1 != RT_NULL)
        rt_thread_startup(tid1);

rt_thread_t tid2 = rt_thread_create("task2", thread2_entry, RT_NULL, 512, 10, 5);
    if (tid2 != RT_NULL)
        rt_thread_startup(tid2);
}
MSH_CMD_EXPORT(sample1_demo, sample1_demo);

static void sample2_demo(void)
{
    rt_thread_t tid1 = rt_thread_create("task1", thread1_entry, RT_NULL, 512, 25, 5);
    if (tid1 != RT_NULL)
        rt_thread_startup(tid1);

rt_thread_t tid2 = rt_thread_create("task2", thread2_entry, RT_NULL, 512, 25, 5);
    if (tid2 != RT_NULL)
        rt_thread_startup(tid2);
}
MSH_CMD_EXPORT(sample2_demo, sample2_demo);

static void sample3_demo(void)
{
    rt_thread_t tid1 = rt_thread_create("task1", thread1_entry, RT_NULL, 512, 10, 5);
    if (tid1 != RT_NULL)
        rt_thread_startup(tid1);

rt_thread_mdelay(600);

rt_thread_t tid2 = rt_thread_create("task2", thread2_entry, RT_NULL, 512, 10, 5);
    if (tid2 != RT_NULL)
        rt_thread_startup(tid2);
}
MSH_CMD_EXPORT(sample3_demo, sample3_demo);

```