[已解决] dfs文件系统可以对二进制文件进行读写不？

发布于 2019-08-16 12:16:40 浏览：2027 订阅该版

1 个回答

tcsun 2019-08-16

这家伙很懒，什么也没写！

用O_BINARY 这个模式是可以的！:D
具体测试代码如下：

[md]void rw_node_info_file(void)
{
    int fd;

uint8_t read_buf[128];
    uint8_t size,i;

fd = open(NODE_INFO_FILE, O_RDWR | O_BINARY | O_CREAT);

if (fd>= 0)
    {   
        // close(fd);
        write(fd, &meter_date[1], 42);
        close(fd);
        rt_kprintf("Write done.\n");
    }
    else
    {
        rt_kprintf("open node_info.no error!\n");
        return;
    }

/* 以只读模式打开 /text.txt 文件 */
    fd = open(NODE_INFO_FILE, O_RDONLY | O_BINARY);
    if (fd>= 0)
    {
        size = read(fd, read_buf, 42);
        close(fd);
        rt_kprintf("read size =%d \n", size);
        if (size < 0)
        {
            rt_kprintf("read date faiul\n");
            return ;
        }
        else
        {
            rt_kprintf("read date=");
            for (i = 0;i<size;i++)
            {
                rt_kprintf("%02X ", read_buf[i]);
            }
            rt_kprintf("\n");
        }
    }
}

MSH_CMD_EXPORT(rw_node_info_file, node info rw test);[/md]

测试结果 OK [/i][i]----------------------------------------------------------------------------------------------------------------------------------------------------------------------------[/i]
[i]msh />rw_node_info_file
Write done.
read size =42 
read date=95 28 07 16 00 08 01 20 19 06 13 00 98 FF 20 04 01 01 00 67 FF 20 19 06 12 00 57 FF 20 19 06 12 00 59 FF 20 04 01 01 08 33 05 
msh />ls
Directory /:
config.ini          21                       
node_info.no        42                       
msh />

[/i]