为什么我detach了信号量还能继续take

发布于 2013-08-14 10:31:10 浏览：2065 订阅该版

```#include "SemaphoreDemo.h"

ALIGN(RT_ALIGN_SIZE)

/*  ?????????? ????????*/
static rt_uint8_t thread1_stack[512];
static rt_uint8_t thread2_stack[512];

/* ?????????? ?????????é */
static struct rt_thread thread_test1;
static struct rt_thread thread_test2;

/*  ??????????*/
static struct rt_semaphore sem;

static void test1_thread_entry(void* parameter)
{
	rt_uint32_t count =0;
	while(1)
	{
		rt_kprintf("test1:%d",count++);
		if(RT_EOK != rt_sem_release(&sem))
			rt_kprintf("sem release failed");
		rt_thread_delay(2);
		if(count==10)
			if(RT_EOK == rt_sem_detach(&sem))
			rt_kprintf("sem detach succeful
");
	}
	
}

static void test2_thread_entry(void* parameter)
{
	rt_err_t result;
	rt_uint32_t count =0;
	while(1)
	{
		result=rt_sem_take(&sem,1);
		if(RT_EOK == result)
			rt_kprintf("test2:%d",count++);
		else if((-RT_ETIMEOUT)==result)
			rt_kprintf("sem take timeout");
		else
			rt_kprintf("sem take failed");
	}
}

rt_err_t SemaphoreDemo_creat(void)
{
	rt_err_t result;
	/* ???¨?????????? ?? ??????0????????????·?????fifo*/
	result = rt_sem_init(&sem,"sem",0,RT_IPC_FLAG_FIFO);
	if(result != RT_EOK)
	{
		rt_kprintf("init  rt_semaphore is failed.
");
		return -1;
	}
	/* ???¨????????1 ?? ?????? 16 ???±???? 2?????????? */
	result = rt_thread_init(&thread_test1,
		"test1",
		test1_thread_entry, RT_NULL,
		(rt_uint8_t*)&thread1_stack[0], sizeof(thread1_stack), 16, 2);
	
	if (result == RT_EOK)
	{
        rt_thread_startup(&thread_test1);
	}	
	else 
	{
		rt_kprintf("thread_test1 creat failed");
		return -1;
	}

/* ???¨????????2 ?? ?????? 15 ???±???? 1?????????? */
	result = rt_thread_init(&thread_test2,
		"test2",
		test2_thread_entry, RT_NULL,
		(rt_uint8_t*)&thread2_stack[0], sizeof(thread2_stack), 15, 1);
	
	if (result == RT_EOK)
	{
        rt_thread_startup(&thread_test2);
	}	
	else 
	{
		rt_kprintf("thread_test2 creat failed");
		return -1;
	}
	return 0;
}```

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