仿真运行出现“tidle0 stack overflow”？

发布于 2020-10-31 20:47:32 浏览：2039 订阅该版

在软件仿真时，会一直运行钩子函数直到提示栈溢出，程序会卡在`_rt_scheduler_stack_check`函数。

```c
/*线程1入口函数*/
void thread1_entey(void *para)
{
    while(1)
    {
        rt_kprintf("thread1 running\r\n");
        rt_thread_mdelay(500);
    }
}

void thread2_idle_hook(void)
{
    while(1)
    {
        rt_kprintf("Test\r\n");
    }
}

int main(void)
 {

/*定义线程结构体*/
    rt_thread_t tid;

/*创建线程*/
    tid = rt_thread_create("thread1",thread1_entey,RT_NULL,10*1024,5,10);

/*判断线程是否创建成功*/
    if(tid != RT_NULL)
    {
        rt_thread_startup(tid);
    }
    else
    {
        rt_kprintf("thread1 create fail!\n");
    }
    
    rt_thread_idle_sethook(thread2_idle_hook);

while(1)
    {
        rt_kprintf("0\r\n");
        rt_thread_mdelay(1000);
        printf("1\r\n");
        rt_thread_mdelay(1000);
    }	 
}
```

![0b36d9840d884f5e53758deff2ff012d.png](/uploads/20201031/0b36d9840d884f5e53758deff2ff012d.png)
![error4.png](/uploads/20201031/970e2e6c84bb59f197cdfe3516bab02b.png)
![error5.png](/uploads/20201031/88e0a28cd502f1dcff875bd3e934e706.png)