RTT移植相关问题

发布于 2020-04-07 12:22:31 浏览：1129 订阅该版

hi， 各位大神，
我移植了RT-Thread，目前时钟tick 能正常中断进入。main也能跑起来了。
但是无法跑多线程。 谁能告诉我应该怎么继续调试下去？ 谢谢
现象：
1  rt_thread_sleep或者 rt_thread_mdelay() 就无反馈了，一直再idle中出不来。
2 多线程也只能执行第后面的那个。下面的是程序。

int main(int argc, char** argv)
{
    int count = 1;

rt_kprintf("Hi, this is RT-Thread!!<br>");

thread_sample();
	return RT_EOK;
	
//    while (count++)
    while (1)
    {
//        set_led(1);
//        rt_thread_sleep(10);
//        set_led(0);
        rt_thread_delay(3);

rt_kprintf("RT-Thread-1<br>");

}

return RT_EOK;
}

#define THREAD_PRIORITY         25
#define THREAD_STACK_SIZE       512
#define THREAD_TIMESLICE        5

/*　使用静态线程时，线程的栈需要设置字节对齐　*/
ALIGN(RT_ALIGN_SIZE)
static rt_uint8_t thread_stack[THREAD_STACK_SIZE];
static struct rt_thread tid1;
static rt_uint8_t thread2_stack[THREAD_STACK_SIZE];
static struct rt_thread tid2;

/* 线程 1 的入口函数 */
static void thread1_entry(void *parameter)
{
    rt_uint32_t count = 0;

while (1)
    {
        rt_kprintf("thread1 count: %d<br>", count ++);
//        rt_thread_mdelay(500);
    }
}

/* 线程 1 的入口函数 */
static void thread2_entry(void *parameter)
{
    rt_uint32_t count = 0;

while (1)
    {
        rt_kprintf("thread2 count: %d<br>", count ++);
//        rt_thread_mdelay(500);
    }
}

/* 线程示例 */
int thread_sample(void)
{
    /* 静态创建线程 */

/* 初始化线程 1，名称是 thread1，入口是 thread1_entry*/
    rt_thread_init(&tid1,
                   "thread1",
                   thread1_entry,
                   RT_NULL,
                   thread_stack,
                   THREAD_STACK_SIZE,
                   THREAD_PRIORITY,
                   THREAD_TIMESLICE);

rt_thread_init(&tid2,
					   "thread2",
					   thread2_entry,
					   RT_NULL,
					   thread2_stack,
					   THREAD_STACK_SIZE,
					   THREAD_PRIORITY,
					   THREAD_TIMESLICE);

/* 启动线程 */
    rt_thread_startup(&tid1);
    rt_thread_startup(&tid2);

return 0;
}

========================
heap: 0x000a900c - 0x040a900c

\ | /
- RT -     Thread Operating System
 / | \     4.0.3 build Apr  7 2020
 2006 - 2020 Copyright by rt-thread team
startup a thread:main with priority:10
thread resume:  main
startup a thread:tidle0 with priority:31
thread resume:  tidle0
Hi, this is RT-Thread!!
startup a thread:thread1 with priority:25
thread resume:  thread1
startup a thread:thread2 with priority:25
thread resume:  thread2
thread1 count: 0
thread1 count: 1
thread1 cothread2 count: 0
thread2 count: 1
thread2 count: 2
thread2 count: 3
thread2 count: 4
thread2 count: 5
thread2 count: 6
thread2 count: 7
thread2 count: 8
thread2 count: 9