如何使用一个串口设备[已解决]

发布于 2013-07-24 12:12:08 浏览：1976 订阅该版

uart1被用作finsh，现在想用另外一个uart2，来进行串口的数据收发操作。
首先在rtconfig.h中
```#define RT_USING_DEVICE
#define RT_USING_UART1
#define RT_USING_UART2```
然后写了个文件
```#include <rtthread.h>
#include <rthw.h>

rt_device_t dev = RT_NULL;

ALIGN(RT_ALIGN_SIZE)
static rt_uint8_t lkt_read_stack[ 512 ];
static struct rt_thread lkt_read_thread;
static void lkt_read_thread_entry(void* parameter)
{
	unsigned char ch;
	while (1)
	{
		while (rt_device_read(dev, 0, &ch, 1) == 1)
		{
			rt_kprintf("0x%02x ",ch);
		}
		rt_thread_delay( RT_TICK_PER_SECOND/2 );
	}
}

void rt_hw_lkt_init(void)
{
	rt_err_t result;
	dev = rt_device_find("uart2");
	if (dev != RT_NULL && rt_device_open(dev, RT_DEVICE_OFLAG_RDWR) == RT_EOK)
	{
		result = rt_thread_init(&lkt_read_thread,
			"lkt_read",
			lkt_read_thread_entry, RT_NULL,
			(rt_uint8_t*)&lkt_read_stack[0], sizeof(lkt_read_stack), 20, 5);
		if (result == RT_EOK)
		{
					rt_thread_startup(&lkt_read_thread);
		}
	}
	else
	{
		rt_kprintf("finsh: can not find device:%s
", "uart2");
	}
}
```
根据usart.c中的定义
```/* USART1_REMAP = 0 */
#define UART1_GPIO_TX		GPIO_Pin_9
#define UART1_GPIO_RX		GPIO_Pin_10
#define UART1_GPIO			GPIOA
#define RCC_APBPeriph_UART1	RCC_APB2Periph_USART1
#define UART1_TX_DMA		DMA1_Channel4
#define UART1_RX_DMA		DMA1_Channel5

#if defined(STM32F10X_LD) || defined(STM32F10X_MD) || defined(STM32F10X_CL)
#define UART2_GPIO_TX	    GPIO_Pin_5
#define UART2_GPIO_RX	    GPIO_Pin_6
#define UART2_GPIO	    	GPIOD
#define RCC_APBPeriph_UART2	RCC_APB1Periph_USART2
#else /* for STM32F10X_HD */
/* USART2_REMAP = 0 */
#define UART2_GPIO_TX		GPIO_Pin_2
#define UART2_GPIO_RX		GPIO_Pin_3
#define UART2_GPIO			GPIOA
#define RCC_APBPeriph_UART2	RCC_APB1Periph_USART2
#define UART2_TX_DMA		DMA1_Channel7
#define UART2_RX_DMA		DMA1_Channel6
#endif```
_说明IO口是D5/D6，~，然后我把A9/A10跟D5/D6连起来了，D5--A10/ D6---A9 _
应该是A3/A2
想的是这样finsh的输出会被uart2读到
现实是没有成功，没有输出。
请教，代码哪里有问题？