【测试】RTT下的UDP通信速率极限是多少？

发布于 2020-04-16 16:41:12 浏览：1564 订阅该版

按照包来计数。

首先进行一波理论计算：

1.ETH驱动通信速率是100M/s.
![1587025864(1).jpg](/uploads/202004/16/163120psbzg0bsdb2gnkd0.jpg)
2.假设我发的每包数据有64个字节  == 512bit
3.按计算器可得到 100，000，000 / 512 = 195312包 ≈ 195kpps
理论上最快1秒可以发195包 64个字节长度的数据呢！

实践：
三两下写好代码，插上网线！！
1.建立socket
2.写好发送任务

```if ((ETH_Sock = socket(AF_INET, SOCK_DGRAM, 0)) == -1)
		{
				rt_kprintf("Socket error<br>"); 
		}
		else
		{
			struct sockaddr_in server_addr;			
			/* 初始化预连接的服务端地址 */
			server_addr.sin_family = AF_INET;
			server_addr.sin_port = htons(4001);
			server_addr.sin_addr.s_addr = IPADDR_ANY;
			rt_memset(&(server_addr.sin_zero), 0, sizeof(server_addr.sin_zero));

/* 绑定socket到服务端地址 */
			if (bind(ETH_Sock, (struct sockaddr *)&server_addr,sizeof(struct sockaddr)) == -1)
			{
					/* 绑定地址失败 */
					closesocket(ETH_Sock);
					rt_kprintf("Bind error<br>");
			}
			else
			{
				ETHLink_Status = 1;
				int flag=1;
				setsockopt(ETH_Sock, SOL_SOCKET, SO_BROADCAST, &flag, sizeof(flag));
			}
		 }``````void APP_UDPETHCOMTx_entry(void* parameter)
{
	uint8_t send_databuf[64]={"abcdefghijklmnopqistuvwxyz"};
	uint8_t len;

client_addr.sin_family = AF_INET;
	client_addr.sin_port = htons(6000);
	client_addr.sin_addr.s_addr = INADDR_BROADCAST;
	rt_memset(&(client_addr.sin_zero), 0, sizeof(client_addr.sin_zero));
	
	if (ETH_Sock != NULL)
	{
		rt_timer_start(timer3);
	}
	while (1)
	{
		/* 发送 */
		if (rt_mq_recv(&mq, send_databuf, sizeof(send_databuf),RT_WAITING_FOREVER) == RT_EOK)
		{
			len=0;
			while(send_databuf[len++] != 0x03)
			{
				if(len >= 50)
					break;
			}
			udptxcount++;
			/* 发送数据到服务远端 */
			sendto(ETH_Sock, send_databuf, len, 0,(struct sockaddr *)&client_addr, sizeof(struct sockaddr));
			memset(send_databuf,0,len);
		}
	 }
}```3.写好定时任务
```  /* 创建定时器 3  周期定时器 */
   timer3 = rt_timer_create("timer3", timeout3, RT_NULL, 1,
                       RT_TIMER_FLAG_PERIODIC);```