【测试】RTT下的UDP通信速率极限是多少？

发布于 2020-04-16 16:41:12 浏览：1552 订阅该版

按照包来计数。

首先进行一波理论计算：

1.ETH驱动通信速率是100M/s.
1587025864(1).jpg
2.假设我发的每包数据有64个字节 == 512bit
3.按计算器可得到 100，000，000 / 512 = 195312包 ≈ 195kpps
理论上最快1秒可以发195包 64个字节长度的数据呢！

实践：
三两下写好代码，插上网线！！
1.建立socket
2.写好发送任务

```if ((ETH_Sock = socket(AF_INET, SOCK_DGRAM, 0)) == -1)
{
rt_kprintf(“Socket error
“);
}
else
{
struct sockaddr_in server_addr;
/ 初始化预连接的服务端地址 /
server_addr.sin_family = AF_INET;
server_addr.sin_port = htons(4001);
server_addr.sin_addr.s_addr = IPADDR_ANY;
rt_memset(&(server_addr.sin_zero), 0, sizeof(server_addr.sin_zero));

        /* 绑定socket到服务端地址 */
        if (bind(ETH_Sock, (struct sockaddr *)&server_addr,sizeof(struct sockaddr)) == -1)
        {
                /* 绑定地址失败 */
                closesocket(ETH_Sock);
                rt_kprintf("Bind error<br>");
        }
        else
        {
            ETHLink_Status = 1;
            int flag=1;
            setsockopt(ETH_Sock, SOL_SOCKET, SO_BROADCAST, &flag, sizeof(flag));
        }
     }``````void APP_UDPETHCOMTx_entry(void* parameter)

{
uint8_t send_databuf[64]={“abcdefghijklmnopqistuvwxyz”};
uint8_t len;

client_addr.sin_family = AF_INET;
client_addr.sin_port = htons(6000);
client_addr.sin_addr.s_addr = INADDR_BROADCAST;
rt_memset(&(client_addr.sin_zero), 0, sizeof(client_addr.sin_zero));
if (ETH_Sock != NULL)
{
    rt_timer_start(timer3);
}
while (1)
{
    /* 发送 */
    if (rt_mq_recv(&mq, send_databuf, sizeof(send_databuf),RT_WAITING_FOREVER) == RT_EOK)
    {
        len=0;
        while(send_databuf[len++] != 0x03)
        {
            if(len >= 50)
                break;
        }
        udptxcount++;
        /* 发送数据到服务远端 */
        sendto(ETH_Sock, send_databuf, len, 0,(struct sockaddr *)&client_addr, sizeof(struct sockaddr));
        memset(send_databuf,0,len);
    }
 }