RT Thtead优先级问题（互斥量章节视频疑问）

发布于 2022-11-13 13:00:51 浏览：564 订阅该版

3 个回答

踩姑娘的小蘑菇 2022-11-14

这家伙很懒，什么也没写！

无量寿经 2022-11-15

这家伙很懒，什么也没写！

无量寿经 2022-11-16

这家伙很懒，什么也没写！

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无量寿经 2022-11-13

这家伙很懒，什么也没写！

源代码如下：

```c
/* 
 * Copyright (c) 2006-2018, RT-Thread Development Team 
 * 
 * SPDX-License-Identifier: Apache-2.0 
 * 
 * Change Logs: 
 * Date           Author       Notes 
 * 2018-08-24     yangjie      the first version 
 */

/*
 * 程序清单：互斥锁例程
 *
 * 互斥锁是一种保护共享资源的方法。当一个线程拥有互斥锁的时候，
 * 可以保护共享资源不被其他线程破坏。线程1对2个number分别进行加1操作
 * 线程2也会对2个number分别进行加1操作。使用互斥量保证2个number值保持一致
 */
#include <rtthread.h>

#define THREAD_PRIORITY         8
#define THREAD_TIMESLICE        5

/* 指向互斥量的指针 */
static rt_mutex_t dynamic_mutex = RT_NULL;
static rt_uint8_t number1,number2 = 0;

ALIGN(RT_ALIGN_SIZE)
static char thread1_stack[1024];
static struct rt_thread thread1;
static void rt_thread_entry1(void *parameter)
{
      while(1)
      {
          /* 线程1获取到互斥量后，先后对number1、number2进行加1操作，然后释放互斥量 */
          rt_mutex_take(dynamic_mutex, RT_WAITING_FOREVER);          
          number1++;
          rt_thread_mdelay(10);
          number2++;          
          rt_mutex_release(dynamic_mutex);
       }	    
}

ALIGN(RT_ALIGN_SIZE)
static char thread2_stack[1024];
static struct rt_thread thread2;
static void rt_thread_entry2(void *parameter)
{     
      while(1)
      {
          /* 线程2获取到互斥量后，检查number1、number2的值是否相同，相同则表示mutex起到了锁的作用 */
          rt_mutex_take(dynamic_mutex, RT_WAITING_FOREVER);
          if(number1 != number2)
          {
            rt_kprintf("not protect.number1 = %d, mumber2 = %d \n",number1 ,number2);
          }
          else
          {
            rt_kprintf("mutex protect ,number1 = mumber2 is %d\n",number1);            
          }
          
           number1++;
           number2++;
           rt_mutex_release(dynamic_mutex);
          
          if(number1 >=50)
              return;      
      }	  
}

/* 互斥量示例的初始化 */
int mutex_sample(void)
{
    /* 创建一个动态互斥量 */
    dynamic_mutex = rt_mutex_create("dmutex", RT_IPC_FLAG_FIFO);
    if (dynamic_mutex == RT_NULL)
    {
        rt_kprintf("create dynamic mutex failed.\n");
        return -1;
    }

rt_thread_init(&thread1,
                   "thread1",
                   rt_thread_entry1,
                   RT_NULL,
                   &thread1_stack[0],
                   sizeof(thread1_stack), 
                   THREAD_PRIORITY, THREAD_TIMESLICE);
    rt_thread_startup(&thread1);
    
    rt_thread_init(&thread2,
                   "thread2",
                   rt_thread_entry2,
                   RT_NULL,
                   &thread2_stack[0],
                   sizeof(thread2_stack), 
                   THREAD_PRIORITY-1, THREAD_TIMESLICE);
    rt_thread_startup(&thread2);
    return 0;
}

/* 导出到 msh 命令列表中 */
MSH_CMD_EXPORT(mutex_sample, mutex sample);
```